1CQ Rank in order, from largest to smallest, the momenta of the objects presented in Figure Q9.1 . Explain.

Step 1 of 5 The momentum of a massive object moving with speed v is the product of its mass and velocity. p=mv Here mis the mass of the object. (a) The linear momentum of the object 1 is: (P x 1m v 1 1 Here, m is the mass of the object 1 1 One physical quantity given in SI i.e velocity another physical quantity given in cgs so we need to convert cgs to Si system of mass Convert the mass of object from g to kg: 1000g = 1kg 1g= 1 kg 1000 1g=0.001kg or 1× 10 kg3 Given m =20g=20× 10 kg 3 1 v = 1 m/s 1 p1= The linear momentum of the object 1 along x- axis is p1= m 1 1 = 20× 10 3 ×1 = 2× 10 2 kg.m/s 2 Thus, the linear momentum of the object 1 along x-axis is 2× 10 kg.m/s .Step 2 of 5 (b)Given m2=20g=20× 10 kg 3 v2= 1 m/s p2= The linear momentum of the object 2 along x- axis is p = m v 2 2 2 = 20× 10 3 ×2 2 = 4× 10 kg.m/s 2 Thus, the linear momentum of the object 2 along x-axis is 4× 10 kg.m/s Step 3 of 5 (c)Given m =10g=10× 10 kg 3 3 v = 2 m/s 3 p3= The linear momentum of the object 3 along x- axis is p3= m 3 3 = 10× 10 3 ×2 = 2× 10 2 kg.m/s Thus, the linear momentum of the object 3 along x-axis is 2× 10 2 kg.m/s