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Solution 63GP Introduction We shall have to calculate net
Chapter 1, Problem 63GP(choose chapter or problem)
Solution 63GP Introduction We shall have to calculate net torque first followed by linear acceleration and time.
Questions & Answers
QUESTION:
Solution 63GP Introduction We shall have to calculate net torque first followed by linear acceleration and time.
ANSWER:Step 1: Given that, diameter = 12 cm Radius R = 6 cm R = 0.06 m Mass of the pulley M = 2.0 kg 1 2 2 Therefore, its moment of inertia I = ×2.0 kg×(0.06) kg.m 2 I = 0.0036 kg.m Let T be the tension of the rope attached to the 4.0 kg mass and T be the tension of the 1 2 rope attached to the 2.0 kg mass. For the 4.0 kg mass, the equation of motion can be written as follows. 4gT = 41 ( a is the acceleration) T =14g4a…..(1) For the 2.0 kg mass, the equation of motion can be written as follows. T 2g = 2a 2 T =22g+2a…..(2) Thus, torque on the pulley = (T T1)0.062N.m (from equations (1) and (2)) Now, the net torque excluding the frictional torque = (T T )0.06 N.m0.50 N.m 1 2 …..(3)