When 2 moles of benzaldehyde are treated with sodium hydroxide, a reaction occurs in

Chapter 20, Problem 20.32

(choose chapter or problem)

When 2 moles of benzaldehyde are treated with sodium hydroxide, a reaction occurs in which 1 mole of benzaldehyde is oxidized (giving benzoic acid) while the other mole of benzaldehyde is reduced (giving benzyl alcohol): H O 1) NaOH 2) H3O+ OH O H H OH This reaction, called the Cannizzaro reaction, is believed to occur via the following mechanism: A hydroxide ion serves as a nucleophile to attack the carbonyl group of benzaldehyde. The resulting intermediate then functions as a hydride reducing agent by delivering a hydride ion to another molecule of benzaldehyde. In this way, one molecule is reduced while the other is oxidized. (a) Draw a mechanism for the Cannizzaro reaction, consistent with the description above. (b) What is the function of H3O+ in the second step? (c) Water alone is not sufficient to accomplish the function of the second step. Explain.

Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.

Becoming a subscriber
Or look for another answer

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back