The active agent in many hair bleaches is hydrogen peroxide. The amount of H2O2 in 14.8

Chapter 4, Problem 4.96

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The active agent in many hair bleaches is hydrogen peroxide. The amount of H2O2 in 14.8 g of hair bleach was determined by titration with a standard potassium permanganate solution: 2MnO4 2(aq) 1 5H2O2(aq) 1 6H1(aq) - 5O2(g) 1 2Mn21(aq) 1 8H2O(l) (a) How many moles of MnO4 2 were required for the titration if 43.2 mL of 0.105 M KMnO4 was needed to reach the end point? (b) How many moles of H2O2 were present in the 14.8-g sample of bleach? (c) How many grams of H2O2 were in the sample? (d) What is the mass percent of H2O2 in the sample? (e) What is the reducing agent in the redox reaction?

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