To effectively stop polymerization, certain inhibitors require the presence of a small

Chapter 13, Problem 13.155

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QUESTION:

To effectively stop polymerization, certain inhibitors require the presence of a small amount of O2. At equilibrium with 1 atm of air, the concentration of O2 dissolved in the monomer acrylic acid (CH2CHCOOH) is 1.6431023 M. (a) What is kH (mol/L?atm) for O2 in acrylic acid? (b) If 0.005 atm of O2 is sufficient to stop polymerization, what is the molarity of O2? (c) What is the mole fraction? (d) What is the concentration in ppm? (Pure acrylic acid is 14.6 M; PO2 in air is 0.2095 atm.)

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QUESTION:

To effectively stop polymerization, certain inhibitors require the presence of a small amount of O2. At equilibrium with 1 atm of air, the concentration of O2 dissolved in the monomer acrylic acid (CH2CHCOOH) is 1.6431023 M. (a) What is kH (mol/L?atm) for O2 in acrylic acid? (b) If 0.005 atm of O2 is sufficient to stop polymerization, what is the molarity of O2? (c) What is the mole fraction? (d) What is the concentration in ppm? (Pure acrylic acid is 14.6 M; PO2 in air is 0.2095 atm.)

ANSWER:

Step 1 of 6

According to the Henry’s law the solubility of the gases can be calculated by the following formula;

                                                         .....................(1)

Here,



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