Condition for non differentiability Suppose f (x) < 0 < f

Solution 38AE In this problem we have to discuss about the condition of non-differentiability. Given: 1. I f x < a then f (x) < 0 < f (x) 2. If x > a then f (x) > 0 > f (x) To prove: f is not differentiable at x = a Consider a very small interval near a , say [a ,a ] + Consider the first condition. “If x < a then f (x) < 0 < f (x)” Now take a very small deviation from a, say x = a Finding the derivative of a , by using mean value theorem. The statement of mean value theorem is given by Mean Value theorem: If f is defined and continuous on the closed interval [a,b]and differentiable on the open interval (a,b)then there is at least one point cin (a,b)that is f(b) f(a) a < c < bsuch that f (c) = ba . Thus f (a )is given by f(a ) = f(aa a f(a) a refers to the value of a that are less than a.So a a < 0. That is a < a Thus using 1. We get, f(a ) < 0 < f (a ) That is f (a ) < 0 and f (a ) > 0 … A Now consider x > a Now take a very small deviation from a, say x = a + Finding the derivative of a , by using mean value theorem. We get, f(a ) f(a) f(a ) = a a + + + a refers to the value of a that are less than a.So a a > 0. That is a > a Thus using 2. We get, f(a ) > 0 > f (a ) That is f (a ) > 0 and f (a ) < 0 ….. B From A and B we can say that + f(a ) = / f(a ) (Since both differ in signs) and f(a ) = / f (a ) (Since both differ in signs) Which is the condition of non-differentiability. Therefore we conclude that f(x) is not differentiable at x = a