a. Show that the point o guaranteed to exist by the Mean Value Theorem for \(f(x)=x^{2}\) on [a, b] is the arithmetic mean of a and b; that is, c = (a + b) / 2.
b. Show that the point c guaranteed to exist by the Mean Value Theorem for f(x) = 1/x on [a, b], where 0 < a < b, is the geometric mean of a and b; that is, \(c=\sqrt{a b}\).
Solution 34AE Step 1 In this problem we have to show that the point cguaranteed to exist by the Mean Value 2 1 Theorem for f(x) = x on [a,b] is arithmetic mean and for f(x) = on [ax b],where 0