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Get Full Access to Calculus: Early Transcendentals - 1 Edition - Chapter 4.6 - Problem 33ae
Get Full Access to Calculus: Early Transcendentals - 1 Edition - Chapter 4.6 - Problem 33ae

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# Mean Value Theorem for quadratic functions Consider the

ISBN: 9780321570567 2

## Solution for problem 33AE Chapter 4.6

Calculus: Early Transcendentals | 1st Edition

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Problem 33AE

Mean Value Theorem for quadratic functions Consider the quadratic function f(x) = Ax +Bx+C where A, B, and C are real numbers with A ? 0. Show that when the Mean Value Theorem is applied to f on the interval [a, b], the number c guaranteed by the theorem is the midpoint of the interval.

Step-by-Step Solution:

Solution 33AE Step 1 In this problem we have to apply mean value theorem to quadratic function. First let us see the statement of mean value theorem Mean Value theorem: If f is defined and continuous on the closed interval [a,b]and differentiable on the open interval (a,b)then there is at least one point cin (a,b)that is f(b) f(a) a < c < bsuch that f(c) = ba

Step 2 of 3

Step 3 of 3

##### ISBN: 9780321570567

The answer to “Mean Value Theorem for quadratic functions Consider the quadratic function f(x) = Ax +Bx+C where A, B, and C are real numbers with A ? 0. Show that when the Mean Value Theorem is applied to f on the interval [a, b], the number c guaranteed by the theorem is the midpoint of the interval.” is broken down into a number of easy to follow steps, and 55 words. This full solution covers the following key subjects: theorem, quadratic, interval, mean, midpoint. This expansive textbook survival guide covers 85 chapters, and 5218 solutions. Calculus: Early Transcendentals was written by and is associated to the ISBN: 9780321570567. The full step-by-step solution to problem: 33AE from chapter: 4.6 was answered by , our top Calculus solution expert on 03/03/17, 03:45PM. This textbook survival guide was created for the textbook: Calculus: Early Transcendentals, edition: 1. Since the solution to 33AE from 4.6 chapter was answered, more than 348 students have viewed the full step-by-step answer.

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