Starting with the symmetrized integrals as in 34, make the substitutions p = 2p/h (where

Chapter 7, Problem 35

(choose chapter or problem)

Starting with the symmetrized integrals as in 34, make the substitutions p = 2p/h (where p is the new variable, h is a constant), f(x) = (x), g() = h/2 (p); show that then (x) = 1 h Z (p)e 2ipx/h dp, (p) = 1 h Z (x)e2ipx/h dx, Z |(x)| 2 dx = Z |(p)| 2 dp. This notation is often used in quantum mechanics.

Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.

Becoming a subscriber
Or look for another answer

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back