The rate law for the reaction is given by . At 25°C, the

Chapter 14, Problem 19QP

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The rate law for the reaction

\(\mathrm{NH}_4^{+}(a q)+\mathrm{NO}_2^{-}(a q) \longrightarrow \mathrm{N}_2(g)+2 \mathrm{H}_2 \mathrm{O}(l)\)

is given by rate \(=k\left[\mathrm{NH}_4^{+}\right]\left[\mathrm{NO}_2^{-}\right]\). At \(25^{\circ} \mathrm{C}\), the rate constant is \(3.0 \times 10^{-4} / \mathrm{M} \cdot \mathrm{s}\). Calculate the rate of the reaction at this temperature if \(\left[\mathrm{NH}_4^{+}\right]=0.36 M\) and \(\left[\mathrm{NO}_2^{-}\right]=0.075 \mathrm{M}\).

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