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At present, the World Anti-Doping Agency has no way to

Chemistry: Atoms First | 1st Edition | ISBN: 9780073511160 | Authors: Julia Burdge, Jason Overby ISBN: 9780073511160 60

Solution for problem 130AP Chapter 15

Chemistry: Atoms First | 1st Edition

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Chemistry: Atoms First | 1st Edition | ISBN: 9780073511160 | Authors: Julia Burdge, Jason Overby

Chemistry: Atoms First | 1st Edition

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Problem 130AP

At present, the World Anti-Doping Agency has no way to detect the use of hypoxic sleeping tents, other than inspection of an athlete’s home. Imagine, however, that a biochemical analysis company is developing a way to determine whether an elevated red blood cell count in an athlete’s blood is the result of such a practice. A key substance in the detection process is the proprietary compound OD17X, which is produced by the combination of two other proprietary compounds, OD1A and OF2A. The aqueous reaction is represented by the equation (a) Write the equilibrium expression for the reaction shown above, (b) Given the equilibrium concentrations at room temperature of [OD1A] = 2.12 M, [OF2A] = 1.56 M, and [OD17X] = 1.01 × 10?4 M, calculate the value of the equilibrium constant (Kc)at room temperature, (c) The OD17X produced is precipitated with another proprietary substance according to the equation Kc for the precipitation equilibrium is 1.0 × 106 at room temperature. Write the equilibrium expression for the sum of the two reactions and determine the value of the overall equilibrium constant, (d) Determine whether or not a mixture with [OD1 A] = 3.00 M, [OF2A] = 2.50 M, and [OD17X] = 2.7 × 10?4 M is at equilibrium and, if not, which direction it will have to proceed in order to achieve equilibrium, (e) Because the production of OD17X is endothermic. it can be enhanced by increasing the temperature. At 250°C, the equilibrium constant for the reaction is 3.8 × 102. If a synthesis at 250°C begins with 1.0 M of each reactant, what will the equilibrium concentrations of reactants and products be?

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Equilibrium Notes­ October 11, 2016 *Reactions at the forward rate and reverse rate have the same rate!* At equilibrium the rate=0 although the reaction rate has not stopped. Reactants Products ­concentration stays constant Kinetics­­­­­­> rate constant k ­can not be written from the balanced equation ­Temp effects ­Collisions ­Ea ­need to know units Equilibrium ­­­­­> equilibrium constant K ­T dependent ­can be written from a balanced equation ­can be treated like an elementary steps in mechanism. ­No units!!! Ex. Forward direction: HC 2H3O2(aq)­­­­­­> H+(aq)+C2H3O 2­ (aq) rate= kf=[HC3H3O2] Reverse direction H+ (aq)+ C2H3O2(aq)­­­­­­>HC2H3O2(

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Chapter 15, Problem 130AP is Solved
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Textbook: Chemistry: Atoms First
Edition: 1
Author: Julia Burdge, Jason Overby
ISBN: 9780073511160

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