In Exercises 23 42, solve the equation (if possible). 35. 1 x 3 + 1 x + 3 = 10 x2 9 36

Chapter 2, Problem 35

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In Exercises 23– 42, solve the equation (if possible).

\(\frac{1}{x-3}+\frac{1}{x+3}=\frac{10}{x^{2}-9}\)

Text Transcription:

1 / x − 3  +  1 / x + 3  =  10 / x^2 − 9

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