RE ? 0 0 1 ,0 ,? forms ?Evaluate the following limits. Check your results by graphing. limln (x+1) x?? x?1

Solution Step 1 x+1 In this problem we have to evaluate the limit xm ln ( x1 ) . x+1 x(1+x) Let lim ln ( x1 ) = lim ln [( x(1 ))] x x x Cancelling the xabove and below we get, (1+ ) = lim ln [( 1 )] x (1 x Now applying the limit we get, = ln [( (1+0))] (10) 1 = ln( )1 = ln (1) = 0 x+1 Thus lim ln ( x1 ) = 0 x