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Get Full Access to Calculus: Early Transcendentals - 1 Edition - Chapter 4 - Problem 22re
Get Full Access to Calculus: Early Transcendentals - 1 Edition - Chapter 4 - Problem 22re

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# Rectangles beneath a curve A rectangle is constructed with

ISBN: 9780321570567 2

## Solution for problem 22RE Chapter 4

Calculus: Early Transcendentals | 1st Edition

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Problem 22RE

Rectangles beneath a curve A rectangle is constructed with one side on the positive x-axis, one side on the positive y-axis, and the vertex opposite the origin on the curve y = cos x, for $$0<x<\pi / 2$$. Approximate the dimensions of the rectangle that maximize the area of the rectangle. What is the area?

Step-by-Step Solution:

Solution Step 1 In this problem a rectangle is constructed with one side on the positive x-axis and one side on the positive y-axis and the vertex opposite to the origin on the curve y = cos x, for 0 < x < /2. We have to find the dimensions of the rectangle that maximize the area of the rectangle.

Step 2 of 2

##### ISBN: 9780321570567

The answer to “?Rectangles beneath a curve A rectangle is constructed with one side on the positive x-axis, one side on the positive y-axis, and the vertex opposite the origin on the curve y = cos x, for $$0<x<\pi / 2$$. Approximate the dimensions of the rectangle that maximize the area of the rectangle. What is the area?” is broken down into a number of easy to follow steps, and 55 words. Calculus: Early Transcendentals was written by and is associated to the ISBN: 9780321570567. Since the solution to 22RE from 4 chapter was answered, more than 430 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Calculus: Early Transcendentals, edition: 1. This full solution covers the following key subjects: rectangle, axis, SIDE, area, curve. This expansive textbook survival guide covers 112 chapters, and 7700 solutions. The full step-by-step solution to problem: 22RE from chapter: 4 was answered by , our top Calculus solution expert on 03/03/17, 03:45PM.

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