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Critical points Find the critical points of the following

Calculus: Early Transcendentals | 1st Edition | ISBN: 9780321570567 | Authors: William L. Briggs, Lyle Cochran, Bernard Gillett ISBN: 9780321570567 2

Solution for problem 10RE Chapter 4

Calculus: Early Transcendentals | 1st Edition

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Calculus: Early Transcendentals | 1st Edition | ISBN: 9780321570567 | Authors: William L. Briggs, Lyle Cochran, Bernard Gillett

Calculus: Early Transcendentals | 1st Edition

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Problem 10RE

Critical points? Find the critical points of the following functions on the given intervals. Identify the absolute minimum and absolute maximum values (if possible). Graph the function to confirm your conclusions. f(x) = x (9 ? x ) on [? 4,4]

Step-by-Step Solution:

Solution Step 1 In this problem we have to find the critical points of the function f(x) = 2x ln x +10and also we have to identify absolute maximum and absolute minimum. First let us see the definitions of critical point, absolute maximum,absolute minimum. Critical point: An interior point cof the domain of a function f at which f (c) = 0or f(c)fails to exist is called a critical point of f Absolute maximum: The highest point over the entire domain of a function or relation is the absolute maximum. Absolute minimum: The lowest point over the entire domain of a function or relation is the absolute minimum. Step 2 Given f(x) = x (9x ) on [4,4] Since f(x) is a polynomial, its derivative exists everywhere. By the definition of critical points, If f has critical points they are points at which f (x) = 0. Here f (x) = x1 31(9x )+x (2x) 3 1 2 2 4 f (x) = x3(9x )2x 3 4 32 x3 3 f (x) = 3x 3 2x Now f (x) = 0 4 3x 3 x3 2x = 0 3 9x 32x 6x = 0 3 2 Multiply throughout by x we get, 2 2 9 x 6x = 0 97x = 0 2 9 x = 7 (Since ln and ecancel each other) x = ± 3 = ± 1.1339 7 Step 4 Thus the critical points are x = 1.1339 and x = 1.1339which lie in the interval [4,4] . These critical points and the end points help us to locate the absolute extrema. Now let us find the value of f(x)at these points. 1 At x = 4, f(4) = (4) (9(4) ) = (1.5874)(916) = 11.1118 At x = 1.1339, 3 2 f(1.1339) = (1.1339) (9(1.1339) ) = (1.04277)(91.2857) = 8.0442 1 At x = 1.1339, f(1.1339) = (1.1339) (9(1.1339) ) = (1.04277)(91.2857) = 8.0442 1 At x = 4, f(4) = (4) (9(4) ) = (1.5874)(916) = 11.1118

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Chapter 4, Problem 10RE is Solved
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Textbook: Calculus: Early Transcendentals
Edition: 1
Author: William L. Briggs, Lyle Cochran, Bernard Gillett
ISBN: 9780321570567

The answer to “Critical points? Find the critical points of the following functions on the given intervals. Identify the absolute minimum and absolute maximum values (if possible). Graph the function to confirm your conclusions. f(x) = x (9 ? x ) on [? 4,4]” is broken down into a number of easy to follow steps, and 41 words. This full solution covers the following key subjects: absolute, points, critical, given, Find. This expansive textbook survival guide covers 85 chapters, and 5218 solutions. Since the solution to 10RE from 4 chapter was answered, more than 333 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 10RE from chapter: 4 was answered by , our top Calculus solution expert on 03/03/17, 03:45PM. This textbook survival guide was created for the textbook: Calculus: Early Transcendentals, edition: 1. Calculus: Early Transcendentals was written by and is associated to the ISBN: 9780321570567.

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Critical points Find the critical points of the following

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