Show that the negative of z = r(cos + i sin ) is z = r[cos( + ) + i sin( + )]
Chapter 7, Problem 174(choose chapter or problem)
Show that the negative of \(z=r(\cos \theta+i\ \sin \theta)\) is
\(-z=r[\cos(\theta+ \pi)+i\ \sin(\theta+ \pi)]\).
Text Transcription:
z=r(cos theta + i sin theta)
-z=r[cos (theta + pi) + i sin (theta + pi)]
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