Solved: In Exercises 129 and 130, show that B is the inverse of A. 129. A = [ 4 7 1 2]
Chapter 8, Problem 130(choose chapter or problem)
The Inverse of a Matrix In Exercises 129 and 130, show that B is the inverse of A.
\(A=\left[\begin{array}{lll}1&1&0\\ 1&0&1\\ 6&2&3\end{array}\right],\quad\ B=\left[\begin{array}{rrr}-2&-3&1\\ 3&3&-1\\ 2&4&-1\end{array}\right]\)
Text Transcription:
A = [_6 2 3 ^1 0 1 ^^1 1 0], B = [_2 4 -1 ^3 3 -1 ^^-2 -3 1]
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