Show that the area of triangle ABC is given by (1/2)ab sin C = (1/2)bc sin A = (1/2)ca sin B.
Step 1 of 3</p>
In this problem we need to prove that area of the triangle ABC is
Step 2 of 3</p>
Given : are the three sides of the triangle.
Construction : Draw a perpendicular from B to AC , let h be the height of the perpendicular drawn.
From the figure the area of the triangle is given by . . . . . . . . . . . . . . (1)
Textbook: Thomas' Calculus: Early Transcendentals
Author: George B. Thomas Jr., Maurice D. Weir, Joel R. Hass
The full step-by-step solution to problem: 9AAE from chapter: 1 was answered by , our top Calculus solution expert on 08/01/17, 02:37PM. This full solution covers the following key subjects: sin, given, area, ABC, show. This expansive textbook survival guide covers 138 chapters, and 9198 solutions. Thomas' Calculus: Early Transcendentals was written by and is associated to the ISBN: 9780321884077. Since the solution to 9AAE from 1 chapter was answered, more than 237 students have viewed the full step-by-step answer. The answer to “Show that the area of triangle ABC is given by (1/2)ab sin C = (1/2)bc sin A = (1/2)ca sin B.” is broken down into a number of easy to follow steps, and 21 words. This textbook survival guide was created for the textbook: Thomas' Calculus: Early Transcendentals , edition: 13.