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# Show that the area of triangle ABC is given by (1/2)ab sin

## Problem 9AAE Chapter 1

Thomas' Calculus: Early Transcendentals | 13th Edition

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Thomas' Calculus: Early Transcendentals | 13th Edition

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Problem 9AAE Problem 9AAE

Show that the area of triangle ABC is given by (1/2)ab sin C = (1/2)bc sin A = (1/2)ca sin B.

Step-by-Step Solution:

Step 1 of 3</p>

In this problem we need to prove that area of the triangle ABC is

Step 2 of 3</p>

Given :  are the three sides of the triangle.

Construction : Draw a perpendicular from B to AC , let h be the height of the perpendicular drawn.

From the figure the area of the triangle is given by . . . . . . . . . . . . . . (1)

We have

Step 3 of 3

##### ISBN: 9780321884077

The full step-by-step solution to problem: 9AAE from chapter: 1 was answered by Sieva Kozinsky, our top Calculus solution expert on 08/01/17, 02:37PM. This full solution covers the following key subjects: sin, given, area, ABC, show. This expansive textbook survival guide covers 138 chapters, and 9198 solutions. Thomas' Calculus: Early Transcendentals was written by Sieva Kozinsky and is associated to the ISBN: 9780321884077. Since the solution to 9AAE from 1 chapter was answered, more than 229 students have viewed the full step-by-step answer. The answer to “Show that the area of triangle ABC is given by (1/2)ab sin C = (1/2)bc sin A = (1/2)ca sin B.” is broken down into a number of easy to follow steps, and 21 words. This textbook survival guide was created for the textbook: Thomas' Calculus: Early Transcendentals , edition: 13th.

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