Solution Found!
Bungee Problem: Lee Per attaches himself to a strong bungee cord and jumps off a bridge
Chapter 1, Problem r1(choose chapter or problem)
Bungee Problem: Lee Per attaches himself to a strong bungee cord and jumps off a bridge. At time t = 3 s, the cord first becomes taut. From that time on, Lee's distance, d, in feet, from the river below the bridge is given by the equation
d = 90 - 80 sin [1.2 (t - 3)]
a. How far is Lee from the water when t = 4?
b. Find the average rate of change of d with respect to t for the interval t = 3.9 to t = 4, and for the interval t = 4 to t = 4.1. Approximately what is the instantaneous rate of change at t = 4? Is Lee going up or going down at time t = 4? Explain.
c. Estimate the instantaneous rate of change of d with respect to t when t = 5.
d. Is Lee going up or down when t = 5? How fast is he going?
e. Which concept of calculus is the instantaneous rate of change?
Questions & Answers
QUESTION:
Bungee Problem: Lee Per attaches himself to a strong bungee cord and jumps off a bridge. At time t = 3 s, the cord first becomes taut. From that time on, Lee's distance, d, in feet, from the river below the bridge is given by the equation
d = 90 - 80 sin [1.2 (t - 3)]
a. How far is Lee from the water when t = 4?
b. Find the average rate of change of d with respect to t for the interval t = 3.9 to t = 4, and for the interval t = 4 to t = 4.1. Approximately what is the instantaneous rate of change at t = 4? Is Lee going up or going down at time t = 4? Explain.
c. Estimate the instantaneous rate of change of d with respect to t when t = 5.
d. Is Lee going up or down when t = 5? How fast is he going?
e. Which concept of calculus is the instantaneous rate of change?
ANSWER:Step 1 of 6
Given that Lee Per attaches himself to a strong bungee cord and jumps off a bridge, Lee's distance from the river below the bridge is given below.
d = 90 - 80 sin [1.2 (t - 3)]