Bungee Problem: Lee Per attaches himself to a strong bungee cord and jumps off a bridge. At time t = 3 s, the cord first becomes taut. From that time on, Lees distance, d, in feet, from the river below the bridge is given by the equation d = 90 80 sin [1.2 (t 3)] a. How far is Lee from the water when t = 4? b. Find the average rate of change of d with respect to t for the interval t = 3.9 to t = 4, and for the interval t = 4 to t = 4.1. Approximately what is the instantaneous rate of change at t = 4? Is Lee going up or going down at time t = 4? Explain. c. Estimate the instantaneous rate of change of d with respect to t when t = 5. d. Is Lee going up or down when t = 5? How fast is he going? e. Which concept of calculus is the instantaneous rate of change?

Lecture 22 Monday, October 12, 201512:04 PM PHCL 2600 Page 1 PHCL 2600 Page 2 PHCL 2600 Page 3 PHCL 2600 Page 4 PHCL 2600 Page 5 PHCL 2600 Page 6 Lecture 23 Tuesday, October 13,...