RE Comparing Variation ?Use the sample data from Exercise to test the claim that the two populations have LDL levels with the same standard deviation. Use a 0.05 significance level. Exercise Comparing Means?The?baseline characteristics?of different treatment groups are often included in journal articles. In one study, 49 subjects treated with raw garlic had LDL cholesterol measurements with a mean of 151 and a standard deviation of 15, while 48 subjects given placebos had LDL cholesterol measurements with a mean of 149 and a standard deviation of 14 (based on data from “Effect of Raw Garlic vs Commercial Garlic Supplements on Plasma Lipid Concentrations in Adults with Moderate Hypercholesterolemia,” by Gardner et al.,?Archives of Internal Medicine,?Vol. 167). Use a 0.05 significance level to test the claim that there is no difference between the mean LDL cholesterol levels of subjects treated with raw garlic and subjects given placebos. Do both groups appear to be about the same?
Solution 10 RE Step 1 From the given information we want to test the claim that the two populations have LDL levels with the same standard deviation. Here, first sample is treatment group because its standard deviation is larger and second sample is placebo group. Then hypothesis is H 0 =1 2 H 1 = 1 / 2 Where a1d ar2 the variance of population. Then the given data is Treatment group : n =49 1 x = 151 1 s1=15 Placebo group : n2=48 x =149 2 s =14 2