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Bob is asked to construct a probability model for rolling a pair of fair dice. He lists
Chapter 5, Problem 17(choose chapter or problem)
Bob is asked to construct a probability model for rolling a pair of fair dice. He lists the outcomes as 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12. Because there are 11 outcomes, he reasoned, the probability of rolling a two must be \(\frac{1}{11}\). What is wrong with Bob's reasoning?
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QUESTION:
Bob is asked to construct a probability model for rolling a pair of fair dice. He lists the outcomes as 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12. Because there are 11 outcomes, he reasoned, the probability of rolling a two must be \(\frac{1}{11}\). What is wrong with Bob's reasoning?
ANSWER:Step 1 of 3
Here, we consider a probability model for rolling a pair of fair dice i.e., for each die, the probability of rolling out a number between 1 to 6 is the same.
\(\mathbb{P}(i)=\frac{1}{6} \quad \forall i \in\{1,2,3,4,5,6\}\)