In the large-sample case, we compare z0 = (k + 0.5) - n 2 2n 2 to -za, regardless of
Chapter 15, Problem 21(choose chapter or problem)
In the large-sample case, we compare z0 = (k + 0.5) - n 2 2n 2 to -za, regardless of whether we are conducting a left-tailed or right-tailed test. Provide a justification for this.
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