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In a game of bridge, West has no aces. What is the

Chapter 3, Problem 1STE

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QUESTION:

Problem 1STE

In a game of bridge, West has no aces. What is the probability of his partner’s having

(a) no aces?

(b) 2 or more aces?

(c) What would the probabilities be if West had exactly 1 ace?

Questions & Answers

QUESTION:

Problem 1STE

In a game of bridge, West has no aces. What is the probability of his partner’s having

(a) no aces?

(b) 2 or more aces?

(c) What would the probabilities be if West had exactly 1 ace?

ANSWER:

Step 1 of 3

Given in a game of bridge, the west has no aces. The partner of west will be east.

There are a total of 52 cards in a deck and each player gets 13 cards.

a). To find the probability of his partner’s having no aces.

     The partner having no ace as well as the west has 13 cards.

      So cards left = 52 - 13

                           = 39

       Of the remaining 39 cards, 4 are aces.

        Then cards left = 39 - 4

                                    = 35

      So, 13 cards have to select from 35 cards in ways.

      Then total ways = .

            P(no aces) =

                       

                              = 0.1818

      Therefore, the probability of his partner’s having no aces is 0.1818.

 

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