Solved: (a) Suppose is a one-to-one differentiable function and its inverse function is
Chapter 3, Problem 3.5.67(choose chapter or problem)
(a) Suppose is a one-to-one differentiable function and its inverse function is also differentiable. Use implicit differentiation to show that ! f #1""!x" ! 1f "! f #1!x"" provided that the denominator is not 0.
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer