Treatment of (CH3)2CHCH(OH)CH2CH3 with TsOH affords two products (M and N) with
Chapter 14, Problem 14.63(choose chapter or problem)
Treatment of (CH3)2CHCH(OH)CH2CH3 with TsOH affords two products (M and N) with molecular formula C6H12. The 1 H NMR spectra of M and N are given below. Propose structures for M and N and draw a mechanism to explain their formation. 3 H 2 H 3 H 1 H ppm 1H NMR of M 9 0 8 1234567 3 H 3 H 3 H 2 H 2 H ppm 1H NMR of N 9 0
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