Identify the structures of each compound from the given data. a. Molecular formula

Organic Chemistry | 3rd Edition | ISBN: 9780077354725 | Authors: Janice Gorzynski Smith

Problem 22.84 Chapter 22

Organic Chemistry | 3rd Edition

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Organic Chemistry | 3rd Edition | ISBN: 9780077354725 | Authors: Janice Gorzynski Smith

Organic Chemistry | 3rd Edition

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Problem 22.84

Identify the structures of each compound from the given data. a. Molecular formula C6H12O2 IR absorption: 1738 cm1 1 H NMR: 1.12 (triplet, 3 H), 1.23 (doublet, 6 H), 2.28 (quartet, 2 H), and 5.00 (septet, 1 H) ppm b. Molecular formula C4H7N IR absorption: 2250 cm1 1 H NMR: 1.08 (triplet, 3 H), 1.70 (multiplet, 2 H), and 2.34 (triplet, 2 H) ppm c. Molecular formula C8H9NO IR absorptions: 3328 and 1639 cm1 1 H NMR: 2.95 (singlet, 3 H), 6.95 (singlet, 1 H), and 7.37.7 (multiplet, 5 H) ppm d. Molecular formula C4H7ClO IR absorption: 1802 cm1 1 H NMR: 0.95 (triplet, 3 H), 1.07 (multiplet, 2 H), and 2.90 (triplet, 2 H) ppm e. Molecular formula C5H10O2 IR absorption: 1750 cm1 1 H NMR: 1.20 (doublet, 6 H), 2.00 (singlet, 3 H), and 4.95 (septet, 1 H) ppm f. Molecular formula C10H12O2 IR absorption: 1740 cm1 1 H NMR: 1.2 (triplet, 3 H), 2.4 (quartet, 2 H), 5.1 (singlet, 2 H), and 7.17.5 (multiplet, 5 H) ppm g. Molecular formula C8H14O3 IR absorptions: 1810 and 1770 cm1 1 H NMR: 1.25 (doublet, 12 H) and 2.65 (septet, 2 H) ppm

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Chemistry 131 Notes Week 1 Section 1.2 || The Scientific Method - Scientific method: a systematic method to research • Observation —> representation —> interpretation - Data • (1) Qualitative: consisting of general observations about the system • (2) Quantitative: comprised of numbers obtained by various measurements of the system - Hypothesis: tentative explanation for a set...

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Chapter 22, Problem 22.84 is Solved
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Textbook: Organic Chemistry
Edition: 3
Author: Janice Gorzynski Smith
ISBN: 9780077354725

Since the solution to 22.84 from 22 chapter was answered, more than 228 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Organic Chemistry, edition: 3. This full solution covers the following key subjects: . This expansive textbook survival guide covers 30 chapters, and 1983 solutions. The answer to “Identify the structures of each compound from the given data. a. Molecular formula C6H12O2 IR absorption: 1738 cm1 1 H NMR: 1.12 (triplet, 3 H), 1.23 (doublet, 6 H), 2.28 (quartet, 2 H), and 5.00 (septet, 1 H) ppm b. Molecular formula C4H7N IR absorption: 2250 cm1 1 H NMR: 1.08 (triplet, 3 H), 1.70 (multiplet, 2 H), and 2.34 (triplet, 2 H) ppm c. Molecular formula C8H9NO IR absorptions: 3328 and 1639 cm1 1 H NMR: 2.95 (singlet, 3 H), 6.95 (singlet, 1 H), and 7.37.7 (multiplet, 5 H) ppm d. Molecular formula C4H7ClO IR absorption: 1802 cm1 1 H NMR: 0.95 (triplet, 3 H), 1.07 (multiplet, 2 H), and 2.90 (triplet, 2 H) ppm e. Molecular formula C5H10O2 IR absorption: 1750 cm1 1 H NMR: 1.20 (doublet, 6 H), 2.00 (singlet, 3 H), and 4.95 (septet, 1 H) ppm f. Molecular formula C10H12O2 IR absorption: 1740 cm1 1 H NMR: 1.2 (triplet, 3 H), 2.4 (quartet, 2 H), 5.1 (singlet, 2 H), and 7.17.5 (multiplet, 5 H) ppm g. Molecular formula C8H14O3 IR absorptions: 1810 and 1770 cm1 1 H NMR: 1.25 (doublet, 12 H) and 2.65 (septet, 2 H) ppm” is broken down into a number of easy to follow steps, and 193 words. The full step-by-step solution to problem: 22.84 from chapter: 22 was answered by Patricia, our top Chemistry solution expert on 01/30/18, 05:21PM. Organic Chemistry was written by Patricia and is associated to the ISBN: 9780077354725.

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