Solution Found!
Find the fallacy in the following proof that 18 > 14 .Multiply both sides of the
Chapter 0, Problem 47(choose chapter or problem)
Find the fallacy in the following "proof" that \(\frac{1}{8}>\frac{1}{4}\). Multiply both sides of the inequality \(3>2\) by \(\log \frac{1}{2}\) to get
\(3 \log _{2}^{1}>2 \log _{2} \frac{1}{2}\)
\(\log \left(\frac{1}{2}\right)^{3}>\log \left(\frac{1}{2}\right)^{2}\)
\(\log _{\frac{1}{8}}>\log \frac{1}{4}\)
\(\frac{1}{8}>\frac{1}{4}\)
Equation Transcirption:
Text Transcription:
⅛ > ¼
3>2
log1/2
3log1/2>2log1/2
log(½)^3>log(½)^2
log1/8>log1/4
Questions & Answers
QUESTION:
Find the fallacy in the following "proof" that \(\frac{1}{8}>\frac{1}{4}\). Multiply both sides of the inequality \(3>2\) by \(\log \frac{1}{2}\) to get
\(3 \log _{2}^{1}>2 \log _{2} \frac{1}{2}\)
\(\log \left(\frac{1}{2}\right)^{3}>\log \left(\frac{1}{2}\right)^{2}\)
\(\log _{\frac{1}{8}}>\log \frac{1}{4}\)
\(\frac{1}{8}>\frac{1}{4}\)
Equation Transcirption:
Text Transcription:
⅛ > ¼
3>2
log1/2
3log1/2>2log1/2
log(½)^3>log(½)^2
log1/8>log1/4
ANSWER:
Step 1 of 2
