In a certain chemical manufacturing process, the dailyweight y of defective chemical

Chapter 4, Problem 45

(choose chapter or problem)

In a certain chemical manufacturing process, the daily weight \(y\) of defective chemical output depends on the total weight \(x\) of all output according to the empirical formula

                                                                                                    \(y=0.01 x+0.00003 x^{2}\)

where \(x\) and \(y\) are in pounds. If the profit is $100 per pound of nondefective chemical produced and the loss is $20 per pound of defective chemical produced, how many pounds of chemical should be produced daily to maximize the total daily profit?

Equation Transcription:

Text Transcription:

y

x

y = 0.01x + 0.00003x^2

x

y

Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.

Becoming a subscriber
Or look for another answer

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back