2126 Find a solution to the initial-value problem. x2y + 2xy = 0, y(1) = 2 [Hint
Chapter 8, Problem 25(choose chapter or problem)
Find a solution to the initial-value problem.
\(x^{2} y^{\prime}+2 x y=0, y(1)=2\) [Hint: Interpret the left-hand side of the equation as the derivative of a product of two functions.]
Equation Transcription:
Text Transcription:
x^2y’ + 2xy = 0, y’(1) = 2
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