2126 Find a solution to the initial-value problem. x2y + 2xy = 0, y(1) = 2 [Hint

Chapter 8, Problem 25

(choose chapter or problem)

Find a solution to the initial-value problem.

\(x^{2} y^{\prime}+2 x y=0, y(1)=2\) [Hint: Interpret the left-hand side of the equation as the derivative of a product of two functions.]

Equation Transcription:

Text Transcription:

x^2y’ + 2xy = 0,  y’(1) = 2

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