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Solution: Each of Exercises 31–36 gives a function ƒ(x), a
Chapter 2, Problem 34E(choose chapter or problem)
Each of Exercises 31–36 gives a function \(f(x)\), a point \(c\), and a positive number \(\epsilon\). Find \(L=\lim _{x \rightarrow c} f(x)\). Then find a number \(\delta>0\) such that for all \(x\)
\(0<|x-c|<\delta \Rightarrow|f(x)-L|<\epsilon\)
\(f(x)=\frac{x^{2}+6 x+5}{x+5}\), \(c=-5\), \(\epsilon=0.05\)
Equation Transcription:
Text Transcription:
f(x)
c
L = lim_x right arrow c f(x)
delta > 0
x
0 < |x-c| < |f(x) - L| < epsilon
f(x) = x^2+6x+5/x + 5, c =-5, epsilon = 0.05
Questions & Answers
QUESTION:
Each of Exercises 31–36 gives a function \(f(x)\), a point \(c\), and a positive number \(\epsilon\). Find \(L=\lim _{x \rightarrow c} f(x)\). Then find a number \(\delta>0\) such that for all \(x\)
\(0<|x-c|<\delta \Rightarrow|f(x)-L|<\epsilon\)
\(f(x)=\frac{x^{2}+6 x+5}{x+5}\), \(c=-5\), \(\epsilon=0.05\)
Equation Transcription:
Text Transcription:
f(x)
c
L = lim_x right arrow c f(x)
delta > 0
x
0 < |x-c| < |f(x) - L| < epsilon
f(x) = x^2+6x+5/x + 5, c =-5, epsilon = 0.05
ANSWER:Solution :
Step 1 of 4 :
In this problem, we have to find the number δ > 0 such that for all x