Show that the line y = mx + b is its own tangent line at any point (x0, mx0 + b).

Solution Step1 of 2:We have to show that the line is its own tangent line at any point

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University Calculus: Early Transcendentals - 2 Edition - Chapter 3.1 - Problem 31e

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ISBN: 9780321717399
65

University Calculus: Early Transcendentals | 2nd Edition

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University Calculus: Early Transcendentals | 2nd Edition

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5

Problem 31E

Show that the line y = mx + b is its own tangent line at any point (x0, mx0 + b).

Step-by-Step Solution:
##### Textbook: University Calculus: Early Transcendentals

##### Edition: 2

##### Author: Joel R. Hass; Maurice D. Weir; George B. Thomas Jr.

##### ISBN: 9780321717399

Step 1 of 2

Solution Step1 of 2:We have to show that the line is its own tangent line at any point

Step 2 of 2
###### Chapter 3.1, Problem 31E is Solved

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This full solution covers the following key subjects: line, own, any, its, point. This expansive textbook survival guide covers 113 chapters, and 6504 solutions. University Calculus: Early Transcendentals was written by and is associated to the ISBN: 9780321717399. This textbook survival guide was created for the textbook: University Calculus: Early Transcendentals , edition: 2. The full step-by-step solution to problem: 31E from chapter: 3.1 was answered by , our top Calculus solution expert on 08/23/17, 12:53PM. Since the solution to 31E from 3.1 chapter was answered, more than 294 students have viewed the full step-by-step answer. The answer to “Show that the line y = mx + b is its own tangent line at any point (x0, mx0 + b).” is broken down into a number of easy to follow steps, and 21 words.

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