Answer: 2326 Find a vector equation of the line tangent to the graphof r(t) at the point

Chapter 12, Problem 25

(choose chapter or problem)

Find a vector equation of the line tangent to the graph of $\mathbf{r}(t)$ at the point $P_{0}$ on the curve.

$\mathbf{r}(t)=t^{2} \mathbf{i}-\frac{1}{t+1} \mathbf{j}+\left(4-t^{2}\right) \mathbf{k} ; P_{0}(4,1,0)$

Equation Transcription:

𝐫 $(t)$

${P}_{0}$

𝐫 $(t)={t}^{2}$ 𝐢 $-\frac{1}{t+1}$ 𝐣 $+(4-{t}^{2})$ 𝐤; ${P}_{0}(4,1,0)$

Text Transcription:

r(t)

P_0

r(t)=t^2i-1/t+1 j+(4-t^2)k;P_0(4,1,0)

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