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Calculus / University Calculus: Early Transcendentals 2 / Chapter 3.9 / Problem 45E

University Calculus: Early Transcendentals | 2nd Edition | ISBN: 9780321717399 | Authors: Joel R. Hass; Maurice D. Weir; George B. Thomas Jr.

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Here is an informal proof that tan-1 1 + tan-1 2 + tan-1 3

Chapter 3, Problem 45E

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QUESTION:

Here is an informal proof that \(\tan ^{-1} 1+\tan ^{-1} 2+\tan ^{-1} 3=\pi\). Explain what is going on.

Equation Transcription:

$ta{n}^{-1}1+ta{n}^{-1}2+ta{n}^{-1}3=\pi{}$

Text Transcription:

tan^-1 1 + tan^-1 2 + tan^-1 3 = pi

Questions & Answers

QUESTION:

Here is an informal proof that \(\tan ^{-1} 1+\tan ^{-1} 2+\tan ^{-1} 3=\pi\). Explain what is going on.

Equation Transcription:

$ta{n}^{-1}1+ta{n}^{-1}2+ta{n}^{-1}3=\pi{}$

Text Transcription:

tan^-1 1 + tan^-1 2 + tan^-1 3 = pi

ANSWER:

Solution :

Step 1 :

In this problem, we have to find the domain and range of the function then sketch the graph of the functions.

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