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Gold can be determined in solutions containing high concentrations of diverseions by

Principles of Instrumental Analysis | 6th Edition | ISBN: 9780495012016 | Authors: Douglas A. Skoog F. James Holler Stanley R. Crouch ISBN: 9780495012016 317

Solution for problem 10-12 Chapter 10

Principles of Instrumental Analysis | 6th Edition

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Principles of Instrumental Analysis | 6th Edition | ISBN: 9780495012016 | Authors: Douglas A. Skoog F. James Holler Stanley R. Crouch

Principles of Instrumental Analysis | 6th Edition

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Problem 10-12

Gold can be determined in solutions containing high concentrations of diverseions by fCP-AES.'9 Aliquots of 50.0 mL of the sample solution were transferredto each of four 100.0 mL volumetric flasks. A solution was preparedcontaining 10.0 mg/L Au in 20% H2SO" and quantities of this solution wereadded to the sample solutions to give 0, 2.5, 5, and 10 mg/L added Au in eachof the llasks. The solutions were made up to a total volume of 100.0 mL, mixed,and analyzed by ICP-AES. The resulting data are presented in the followingtable.Added An,mg/L0.02.55.010.012,56819,32426,62240,021(it) Use a spreadsheet to perform a least-squares analysis to determine theslope, intercept, and regression statistics, including the standard deviationabout regression.(b) Use your results to find the concentration of gold in the sample solutionin mg/L.(c) The known concentration of gold in the sample is 8.51 mg/L. Test the hypothesisthat your result is equal to this value at the 95% confidence level.(d) Compare your result to the result reported by Whitehead et aI., and commenton any differences.

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Chapter 4 Thursday, February 4, 2016 4:48 PM Chemical bond: attractive force that holds atoms together An ion forms when an atom's number of electrons changes. Metals lose valence electrons Nonmetals gain valence electrons Zinc and cadmium is +2, silver is +1 ALUMINUM AND GALLIUM….ZINC, AND CADMIUM. ANNNDDDDDDSILVER. Group VIIA nonmetals gain 1 e: -1 F- is fluoride ion Cl- is chloride...

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Chapter 10, Problem 10-12 is Solved
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Textbook: Principles of Instrumental Analysis
Edition: 6
Author: Douglas A. Skoog F. James Holler Stanley R. Crouch
ISBN: 9780495012016

The full step-by-step solution to problem: 10-12 from chapter: 10 was answered by , our top Chemistry solution expert on 03/02/18, 06:21PM. Since the solution to 10-12 from 10 chapter was answered, more than 216 students have viewed the full step-by-step answer. Principles of Instrumental Analysis was written by and is associated to the ISBN: 9780495012016. This textbook survival guide was created for the textbook: Principles of Instrumental Analysis , edition: 6. This full solution covers the following key subjects: . This expansive textbook survival guide covers 34 chapters, and 619 solutions. The answer to “Gold can be determined in solutions containing high concentrations of diverseions by fCP-AES.'9 Aliquots of 50.0 mL of the sample solution were transferredto each of four 100.0 mL volumetric flasks. A solution was preparedcontaining 10.0 mg/L Au in 20% H2SO" and quantities of this solution wereadded to the sample solutions to give 0, 2.5, 5, and 10 mg/L added Au in eachof the llasks. The solutions were made up to a total volume of 100.0 mL, mixed,and analyzed by ICP-AES. The resulting data are presented in the followingtable.Added An,mg/L0.02.55.010.012,56819,32426,62240,021(it) Use a spreadsheet to perform a least-squares analysis to determine theslope, intercept, and regression statistics, including the standard deviationabout regression.(b) Use your results to find the concentration of gold in the sample solutionin mg/L.(c) The known concentration of gold in the sample is 8.51 mg/L. Test the hypothesisthat your result is equal to this value at the 95% confidence level.(d) Compare your result to the result reported by Whitehead et aI., and commenton any differences.” is broken down into a number of easy to follow steps, and 164 words.

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