A 40.00-mL aliquot of 0.0500 M HNO, is diluted to 75.0 mL and titrated with0.0800 M
Chapter 23, Problem 23-24(choose chapter or problem)
A 40.00-mL aliquot of 0.0500 M HNO, is diluted to 75.0 mL and titrated with0.0800 M Ce'+. Assume the hydrogen ion concentration is at 1.00 M throughoutthe titration. (Use 1.44 V for the formal potential of the cerium system.)(a) Calculate thc potential of the indicator electrode with respect to a AgAgCl(sat'd)reference electrode after the addition of 5.00, 10.00. 1500.20.00,25.00,40.00,45.00,49.00,49.50,49.60.49.70. 49.80. 49.90. 49.95, 49.99.50.00.5001. 50.05. 50.10, 50.20. 50.30, 50.40. 50.50, 51.00, 55.00, 60.00, 75.00,and 90.00 mL of cerium(IV).(b) Construct a titration curve for these data.(c) Generate a first- and second-derivative curve for these data." Does the volumeat which the second-derivative curve crosses zero correspond to thc theoreticalequivalence point" Why or why not"
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