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The acceleration of a particle moving back and forth on a
Chapter 5, Problem 78E(choose chapter or problem)
The acceleration of a particle moving back and forth on a line is \(a=d^{2} s / d t^{2}=\pi^{2} \cos \pi t \mathrm{~m} / \mathrm{sec}^{2} \\\) for all \(t\). If \(s = 0\) and \(v=8 \mathrm{~m} / \mathrm{sec}\) when \(t=0\), find s when \(t = 1\) sec.
Text Transcription:
Text Transcription:
a = d^2s/dt^2 = pi^2 cos pi t m/sec^2
s=0
v= 8 m/sec
t=0
=1
Questions & Answers
QUESTION:
The acceleration of a particle moving back and forth on a line is \(a=d^{2} s / d t^{2}=\pi^{2} \cos \pi t \mathrm{~m} / \mathrm{sec}^{2} \\\) for all \(t\). If \(s = 0\) and \(v=8 \mathrm{~m} / \mathrm{sec}\) when \(t=0\), find s when \(t = 1\) sec.
Text Transcription:
Text Transcription:
a = d^2s/dt^2 = pi^2 cos pi t m/sec^2
s=0
v= 8 m/sec
t=0
=1
ANSWER:
SOLUTION
Step 1 of 7
Here, we have to find the position of the moving particle s when time .
Given that the acceleration for all t.
It is also given that and
when
.