For the circuit in Fig. 7.51(a), neglect the base current IB in comparison with the

Chapter 7, Problem 7.104

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For the circuit in Fig. 7.51(a), neglect the base current IB in comparison with the current in the voltage divider. It is required to bias the transistor at IC = 1 mA, which requires selecting RB1 and RB2 so that VBE = 0.710 V. If VCC = 3 V, what must the ratio RB1/RB2 be? Now, if RB1 and RB2 are 1% resistors, that is, each can be in the range of 0.99 to 1.01 of its nominal value, what is the range obtained for VBE? What is the corresponding range of IC? If RC = 2 k, what is the range obtained for VCE? Comment on the efficacy of this biasing arrangement.

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