Let T = 3 2 L as in Exercise 20. The numbers in the second column of Table 4 are

Chapter 2, Problem 36

(choose chapter or problem)

Let T = 3 2 L as in Exercise 20. The numbers in the second column of Table 4 are increasing, and those in the last column are decreasing. Explain why in terms of the graph of T as a function of L. Also, explain graphically why the instantaneous rate of change atL = 3 lies between 0.43299 and 0.43303. TABLE 4 Average Rates of Change of T with Respect to L Average rate Average rate Interval of change Interval of change [3, 3.2] 0.42603 [2.8, 3] 0.44048 [3, 3.1] 0.42946 [2.9, 3] 0.43668 [3, 3.001] 0.43298 [2.999, 3] 0.43305 [3, 3.0005] 0.43299 [2.9995, 3] 0.43303

Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.

Becoming a subscriber
Or look for another answer

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back