Show that f [x0, x1,... , xn , x] = f (n+1) ((x)) (n + 1)! , for some (x). [Hint: From

Chapter 3, Problem 3.2.20

(choose chapter or problem)

Show that f [x0, x1,... , xn , x] = f (n+1) ((x)) (n + 1)! , for some (x). [Hint: From Eq. (3.3), f (x) = Pn (x) + f (n+1) ((x)) (n + 1)! (x x0)(x xn ). Considering the interpolation polynomial of degree n + 1 on x0, x1,... , xn , x, we have f (x) = Pn+1(x) = Pn (x) + f [x0, x1,... , xn , x](x x0)(x xn ).]

Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.

Becoming a subscriber
Or look for another answer

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back