Approximate the solutions to the following elliptic partial differential equations

Chapter 12, Problem 12.1.3

(choose chapter or problem)

Approximate the solutions to the following elliptic partial differential equations, using Algorithm 12.1: a. 2u x 2 + 2u y2 = 0, 0 < x < 1, 0 < y < 1; u(x, 0) = 0, u(x, 1) = x, 0 x 1; u(0, y) = 0, u(1, y) = y, 0 y 1. Use h = k = 0.2, and compare the results to the actual solution u(x, y) = xy. b. 2u x 2 + 2u y2 = (cos(x + y) + cos(x y)), 0 < x < , 0 < y < 2 ; u(0, y) = cos y, u(, y) = cos y, 0 y 2 , u(x, 0) = cos x, u x, 2 = 0, 0 x . Use h = /5 and k = /10, and compare the results to the actual solution u(x, y) = cos x cos y. c. 2u x 2 + 2u y2 = (x 2 + y2)exy , 0 < x < 2, 0 < y < 1; u(0, y) = 1, u(2, y) = e2y , 0 y 1; u(x, 0) = 1, u(x, 1) = ex , 0 x 2. Use h = 0.2 and k = 0.1, and compare the results to the actual solution u(x, y) = exy . d. 2u x 2 + 2u y2 = x y + y x , 1 < x < 2, 1 < y < 2; u(x, 1) = x ln x, u(x, 2) = x ln(4x 2 ), 1 x 2; u(1, y) = y ln y, u(2, y) = 2y ln(2y), 1 y 2. Use h = k = 0.1, and compare the results to the actual solution u(x, y) = xy ln xy.

Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.

Becoming a subscriber
Or look for another answer

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back