Let S = n=1 an. Arguing as in Exercise 83, show that M n=1 an + M+1 f (x) dx S M +1 n=1

Chapter 10, Problem 85

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Let S = n=1 an. Arguing as in Exercise 83, show that M n=1 an + M+1 f (x) dx S M +1 n=1 an + M+1 f (x) dx 4 Conclude that 0 S M n=1 an + M+1 f (x) dx aM+1 5 This provides a method for approximating S with an error of at most aM+1.

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