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Solved: Finding the Mean of a Frequency Distribution In
Chapter 2, Problem 51E(choose chapter or problem)
Problem 51E
Finding the Mean of a Frequency Distribution In Exercise, approximate the mean of the frequency distribution
Ages The ages of the residents of Medicine Lake, Montana, in 2010 (Source: U.S. Census Bureau)
Age |
Frequency |
0 – 9 |
44 |
10 –19 |
66 |
20 –29 |
32 |
30 –39 |
53 |
40 – 49 |
35 |
50 – 59 |
31 |
60 – 69 |
23 |
70 –79 |
13 |
80 – 89 |
2 |
Questions & Answers
QUESTION:
Problem 51E
Finding the Mean of a Frequency Distribution In Exercise, approximate the mean of the frequency distribution
Ages The ages of the residents of Medicine Lake, Montana, in 2010 (Source: U.S. Census Bureau)
Age |
Frequency |
0 – 9 |
44 |
10 –19 |
66 |
20 –29 |
32 |
30 –39 |
53 |
40 – 49 |
35 |
50 – 59 |
31 |
60 – 69 |
23 |
70 –79 |
13 |
80 – 89 |
2 |
ANSWER:
Solution :
Step 1 of 1:
Given the ages of the residents of Medicine Lake, Montana, in 2010.
Age |
Frequency (f) |
0 – 9 |
44 |
10 – 19 |
66 |
20 – 29 |
32 |
30 – 39 |
53 |
40 – 49 |
35 |
50 – 59 |
31 |
60 – 69 |
23 |
70 –79 |
13 |
80 – 89 |
2 |
Our goal is:
We need to find the mean of the frequency distribution.
Now we have to find the midpoint.
The Midpoint formula is
Midpoint =