Coffee Contents During a quality assurance check, the actual coffe contents (in ounces) of six jars of instant coffee were recorded as 6.03, 5.59, 6.40, 6.00, 5.99, and 6.02.
(a) Find the mean and the median of the coffee content.
(b) The third value was incorrectly measured and is actually 6.04. Find the mean and the median of the coffee content again.
(c) Which measure of central tendency, the mean or the median, was affected more by the data entry error?
Step 1 of 3
Given that the coffee content of 6 jars were recorded as follows
6.03, 5.59, 6.40, 6.00, 5.99, 6.02
a) We have to find the mean and median of the coffee content
Means is the average of all the values
Median is the middle value of the data set
To find median first arrange the values in the ascending order
5.59, 5.99, 6.00, 6.02, 6.03, 6.40
=(6+1)/2 th value
=(3rd value+4th value)/2