Solution Found!
Conduct the hypothesis test and provide the test
Chapter 11, Problem 8BSC(choose chapter or problem)
Conduct the hypothesis test and provide the test statistic, critical value, and/or P-value, and state the conclusion. Flat Tire and Missed Class ?A classic story involves four carpooling students who missed a test and gave as an excuse a flat tire. On the makeup test, the instructor asked the students to identify the particular tire that went flat. If they really didn’t have a flat tire, would they be able to identify the same tire? The author asked 41 other students to identify the tire they would select. The results are listed in the following table (except for one student who selected the spare). Use a 0.05 significance level to test the author’s claim that the results fit a uniform distribution. What does the result suggest about the ability of the four students to select the same tire when they really didn’t have a flat?
Questions & Answers
QUESTION:
Conduct the hypothesis test and provide the test statistic, critical value, and/or P-value, and state the conclusion. Flat Tire and Missed Class ?A classic story involves four carpooling students who missed a test and gave as an excuse a flat tire. On the makeup test, the instructor asked the students to identify the particular tire that went flat. If they really didn’t have a flat tire, would they be able to identify the same tire? The author asked 41 other students to identify the tire they would select. The results are listed in the following table (except for one student who selected the spare). Use a 0.05 significance level to test the author’s claim that the results fit a uniform distribution. What does the result suggest about the ability of the four students to select the same tire when they really didn’t have a flat?
ANSWER:Solution 8BSC Step 1 By using = 0.05 significance level to test the author’s claim that the results fit a uniform distribution. The results are listed in the following table. observed expected O - E (O - E)² / E 11 10.000 1.000 0.100 15 10.000 5.000 2.500 8 10.000 -2.000 0.400 6 10.000 -4.000 1.600 40 40.000 0.000 4.600 Expected frequency = 10 is same for all categories. The Test Statistic here is (O E ) 2 i i = = 4.6 E i Where O iObserved frequency E = Expected frequency i