Figure 4.28 shows the second derivative of h(x) for 2 x 1. If h (1) = 0 and h(1) = 2
Chapter 4, Problem 41(choose chapter or problem)
Figure 4.28 shows the second derivative of h(x) for 2 x 1. If h (1) = 0 and h(1) = 2, (a) Explain why h (x) is never negative on this interval. (b) Explain why h(x) has a global maximum at x = 1. (c) Sketch a possible graph of h(x) for 2 x 1.
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