In Exercise?, ?conduct the hypothesis test and provide the test statistic, critical value, and/or P-value, and state the conclusion. Police Calls? Repeat the preceding exercise using these observed frequencies for police calls received during the month of March: Monday (208); Tuesday (224); Wednesday (246); Thursday (173); Friday (210); Saturday (236); Sunday (154). What is a fundamental error with this analysis?

Solution 16BSC Step 1 By using = 0.01 significance level to test the claim that the different days of the week have the same frequencies of police calls. We are testing Chi-square test (using SPSS). DataWeight casesFrequencies. Then, Descriptive Cross tabs-rows Colour column Result Statistics Chi-squareOK The Output is as shown below 2 Hence, we have = 31.963 with 6 degrees of freedom and P-value = 0.000 at 1% level of significance. (The smaller P-value is, the stronger the evidence against H and in 0vor of H . If 1 P-value is small like 0.01 or smaller, we may conclude that the null hypothesis H is 0 strongly rejected in favor of H . If P-value is between 0.05 P-value 0.01, we may 1 conclude that the null hypothesis H is r0ected in favor of H . In ot1r cases, i.e., P-value > 0.05, we may conclude that the null hypothesis H is accep0d) Since P-value is smaller we reject the null hypothesis at 1% level of significance and conclude that there is no sufficient evidence to claim that the different days of the week have the same frequencies of police calls. Here we see that Monday (208); Tuesday (224); Wednesday (246); Thursday (173); Friday (210); Saturday (236); Sunday (154) has the same frequencies of phone calls but the analysis of the result shows that different days of the week have the different frequencies of police calls.