A particle lies on a line perpendicular to a thin circular ring and through its center
Chapter 0, Problem 97(choose chapter or problem)
A particle lies on a line perpendicular to a thin circular ring and through its center. The radius of the ring is a, and the distance from the point to the center of the ring is y. For a positive constant K, the gravitational force exerted by the ring on the particle is given by F = Ky (a2 + y2)3/2 , If y is increasing, how is F changing with respect to time, t, when (a) y = 0 (b) y = a/2 (c) y = 2a
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