ICU Patients? Listed below are the ages of randomly selected patients in intensive care units (based on data from “A Multifaceted Intervention for Quality Improvement in a Network of Intensive Care Units,” by Scales et al., ?Journal of the American Medical Association,? Vol. 305, No. 4). Find the mean, median, and standard deviation. Based on the results, is an age of 16 years ?unusual?? Why or why not?
Solution 3CRE Step1: From the above given problem we have ICU Patients Listed below are the ages of randomly selected patients in intensive care units 38,64,35,67,42,29,68,62,74,58. Step2: Our aim is to find mean, median and standard deviation Based on the results,we need to check is an age of 16 years u nusual Why or why not Step: 1).Mean: mean is the average of all numbers or It is the average of sum of all values divided by number of values. Mean can be calculated by using the formula x i=1i X = N 38+64+35+6+42+29+68+62+74+58 = 10 = 53.7 Therefore, the mean value is X = 53.7 2).median: Median is middle value in data set,The median of the data is found by arranging the data in ascending order first. 29,35,38,42,58,62,64,67,68,74 Now the median is given by Median = n+1, if data set is even 2 n Median = 2, if data set is odd Therefore, median = 10+1 112 = 2 = 5.5 5.5th item is the median value what we have arranged in ascending order i.e, Hence we will take mean of 5th and 6th item which is 58 and 62 respectively. So the median will be 60 years. 3).standard deviation: 10 2 (i x) It is square root of variance and it is given by S = i =10 = 16.09 Therefore standard deviation is S = 16.09 years An age of 16 years is unusual because it is away from standard deviation as well as it will alter the mean value significantly.
