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Get Full Access to Elementary Statistics - 12 Edition - Chapter 11.3 - Problem 15bsc
Get Full Access to Elementary Statistics - 12 Edition - Chapter 11.3 - Problem 15bsc

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# In Exercise, test the given claim.Clinical Trial of

ISBN: 9780321836960 18

## Solution for problem 15BSC Chapter 11.3

Elementary Statistics | 12th Edition

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Problem 15BSC

Problem  15BSC

In Exercise, test the given claim.

Clinical Trial of Echinacea In a clinical trial of the effectiveness of echinacea for preventing colds, the results in the table below were obtained (based on data from “An Evaluation of Echinacea Angustifolia in Experimental Rhinovirus Infections,” by Turner et al., New England Journal of Medicine, Vol. 353, No. 4). Use a 0.05 significance level to test the claim that getting a cold is independent of the treatment group. What do the results suggest about the effectiveness of echinacea as a prevention against colds?

 Treatment Group Placebo Echinacea: 20% extract Echinacea: 60% extract Got a Cold 88 48 42 Did Not Get a Cold 15 4 10

Step-by-Step Solution:

Step 1 of 2

 Treatment Group Placebo Echinacea: 20% extract Echinacea: 60% extract Total Got a Cold 88 48 42 178 Did Not Get a Cold 15 4 10 29 Total 103 52 52 207

The solution to this problem takes four steps: (1) state the hypotheses, (2) formulate an analysis plan, (3) analyze sample data, and (4) interpret results. We work through those steps below:

State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.

H0: The claim that the amount of smoking is independent of seat belt use

H1: The claim that the amount of smoking is not independent of seat belt use

Formulate an analysis plan. For this analysis, the significance level is 0.05. Using sample data, we will conduct a chi-square test for independence.

Applying the chi-square test for independence to sample data, we compute the degrees of freedom, the expected frequency counts, and the chi-square test statistic.

DF = (r - 1)  (c - 1) = (2 - 1)  (3 - 1) = 2

 Treatment Group Placebo Echinacea: 20% extract Echinacea: 60% extract Total Got a Cold 88 48 42 178 Did Not Get a Cold 15 4 10 29 Total 103 52 52 207

= 88.57

= 44.7149

= 44.7149

= 14.4299

= 7.285

= 7.285

 SL. No. O E (O - E )2 (O - E)2/E 1 88 88.57 0.3249 0.003668 2 48 44.7149 10.79188 0.241349 3 42 44.7149 7.370682 0.164837 4 15 14.4299 0.325014 0.022524
Step 2 of 1

##### ISBN: 9780321836960

This textbook survival guide was created for the textbook: Elementary Statistics, edition: 12. Elementary Statistics was written by and is associated to the ISBN: 9780321836960. The full step-by-step solution to problem: 15BSC from chapter: 11.3 was answered by , our top Statistics solution expert on 03/15/17, 10:30PM. This full solution covers the following key subjects: echinacea, claim, treatment, results, RAC. This expansive textbook survival guide covers 121 chapters, and 3629 solutions. The answer to “In Exercise, test the given claim.Clinical Trial of Echinacea In a clinical trial of the effectiveness of echinacea for preventing colds, the results in the table below were obtained (based on data from “An Evaluation of Echinacea Angustifolia in Experimental Rhinovirus Infections,” by Turner et al., New England Journal of Medicine, Vol. 353, No. 4). Use a 0.05 significance level to test the claim that getting a cold is independent of the treatment group. What do the results suggest about the effectiveness of echinacea as a prevention against colds? Treatment Group PlaceboEchinacea: 20% extractEchinacea: 60% extractGot a Cold884842Did Not Get a Cold15410” is broken down into a number of easy to follow steps, and 102 words. Since the solution to 15BSC from 11.3 chapter was answered, more than 609 students have viewed the full step-by-step answer.

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